The solution to a math problem is the correct answer for the problem. The solution to an equation is a set of one or more values that, when substituted for a variable, make an equation or system true or consistent. To solve a math problem is to find the solution of the problem.
For example, given the equation x + 3 = 5, the solution is x = 2. x = 2 satisfies the equation x + 3 = 5. Try substituting 2 for x in the equation. The equation becomes 2 + 3 = 5. Since this is a true statement, we know that 2 is a solution to the equation.
An extraneous solution is a apparent solution that does not satisfies the equation or system. Extraneous solutions can occur when multiplying both sides of an equation by a variable, and by squaring both sides of an equation:
| Step | Equation | Description |
|---|---|---|
| 1 | ![]() |
This is the equation to solve. |
| 2 | ![]() |
Square both sides of the equation. This is the step where and extraneous solution is introduced. Expand both sides of the equation by applying the exponents. |
| 3 | ![]() |
Subtract x from both sides of the equation. |
| 4 | ![]() |
Factor the left hand side of the equation. |
| 5 | ![]() |
The factors imply solutions of 4 and 1. |
| 6 | ![]() |
Check the solution x = 4 by substituting 4 for x in the original equation. The equation now simplifies to 2 = 2. Since this is a true statement that satisfies the equation, 2 is a solution to the equation. 2 is not an extraneous solution to the equation. |
| 7 | ![]() |
Check the solution x = 1 by substituting 1 for x in the original equation. The equation now simplifies to -1 = 1. Since this is a false statement, 1 does not satisfy the equation. 1 is a not solution to the equation. 1 is an extraneous solution. |
| Table 1: Finding an extraneous solution. | ||
| # | A | B | C | D |
| E | F | G | H | I |
| J | K | L | M | N |
| O | P | Q | R | S |
| T | U | V | W | X |
| Y | Z |
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