An inequality is an relation that uses one of the following relationship operators:
Inequality Operator | Description | Graph |
---|---|---|
< | Less than | |
≤ <= | Less than or equal to | |
≠ != # | Not equal to; This could also be called less than or greater than | |
≥ >= | Greater than or equal to | |
> | Greater than | |
Table 1: Inequality operators |
A compound inequality has more than one inequality operator.
Inequalities can be solved like equalities with one important difference: If the inequality is multiplied by a negative number, < changes to > and > changes to <. Take the true equation
When graphing one variable inequalities on a number line, start with the end point(s). If the variable can be equal to the end point, draw a solid circle on the number line: . If the variable can not be equal to the end point, draw a a hollow circle on the number line: . Then draw the lines representing the inequalities. Table 2 shows some examples.
Equation | Graph | Explanation |
---|---|---|
a < 5 | Since 5 is the endpoint, the circle is on 5. The inequality is '<' so the circle is hollow. Since a < 5, the arrow goes to the left. | |
a ≤ -3 | Since -3 is the endpoint, the circle is on -3. The inequality is '≤' so the circle is solid. Since a ≤ -3, the arrow goes to the left. | |
t ≥ 2 | Since 2 is the endpoint, the circle is on 2. The inequality is '≥' so the circle is solid. Since a ≥ 2, the arrow goes to the right. | |
t > -6 | Since -6 is the endpoint, the circle is on -6. The inequality is '>' so the circle is hollow. Since t > -6, the arrow goes to the right. | |
-4 < r ≤ 2 | Since -4 and 2 are the endpoints, the circles are on -4 and 2. The inequality for -4 is '<' so that circle is hollow. The inequality for 2 is '≤' so that circle is solid. | |
1 > r or r ≥ 3 | Since 1 and 3 are the endpoints, the circles are on 1 and 3. The inequality for 1 is '<' so that circle is hollow. The inequality for 3 is '≥' so that circle is solid. | |
Table 2: Graphs of one variable inequalities. |
Inequalities are solved much the same was as equalities. Here is an example solving the inequality -x + 5 ≤ -5.
Step | Inequality | Explanation |
---|---|---|
1 | -x + 5 ≤ -5 | Original equation |
2 | -x + 5 - 5 ≤ -5 - 5 ⇒ -x ≤ -10 | Subtract 5 from both sides |
3 | -1·-x ≥ -1·-10 ⇒ x ≥ 10 | Multiply both sides by -1. Since the inequality is being multiplied by a negative number, change the ≤ to ≥. |
4 | 11 ≥ 10 | Substitute 11 in for x in the original equation to check the work. Since 11 ≥ 10, 11 is a solution to the inequality. |
Table 3: Solving an inequality |
# | A | B | C | D |
E | F | G | H | I |
J | K | L | M | N |
O | P | Q | R | S |
T | U | V | W | X |
Y | Z |
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