Most math problems you will find in algebra involve solving equations. The idea is to find a solution to the equation. A solution is a set of one or more values that, when substituted for the variable(s), make the equation true.
Solving equations is one of the most important math skills to learn. There are several classes of equations you will find in your studies:
What Does it Mean to Solve an Equation?
Properties of Numbers Used to Solve Equations
Using Addition and Subtraction to Solve an Equation
Using Multiplication to Solve an Equation
Using Division to Solve an Equation
Using the Distributive Property to Solve an Equation
Solving an Equation Graphically
Solving a Quadratic Equation
Solving a Multiple Variable Equation
To solve an equation is to find out what the equation tells one about the possible values of one or more variables. Take the equation x+3 = 2x-1. What does this equation tell one about the value of x? To find out, solve the equation.
Solving a one variable linear equation involves getting the variable on one side of the equals sign by itself. To do this one uses the properties of numbers.
Property | Example | Description |
---|---|---|
Property of adding zero | Given a real number x; x+0 = x | Zero added to any number equals the original number. |
Addition property of equality | Given three real numbers a, b, and c; if a=b then a+c = b+c | If two numbers are equal, after adding the same value to each number, the sum remain equal. |
Subtraction property of equality | Given three real numbers a, b, and c; if a=b then a-c = b-c | If two numbers are equal, after subtracting the same value from each number, the difference remain equal. |
Property of multiplying by 1 | Given a real numbers x; 1·x = x | Any number multiplied by 1 equals itself. |
Distributive property of multiplication over addition and subtraction | Give 3 real numbers a, b, and c; a(b+c) = ab+ac | A number multiplied by a sum is equal to the sum of the number multiplied by each term. |
Transitive property of equality | Given three real numbers a, b, and c; if a=b and b=c then a=c | If two numbers are equal to the same other number, they are equal to each other. |
Table 1: Properties of numbers used to solve an equation |
Start with the equation x+3 = 5. Since the goal is to get x by itself, one needs to do something about the 3 that is added to the x. To undo addition, use subtraction:
Step | Equation | Description |
---|---|---|
1 | x+3 = 5 | Original equation |
2 | (x+3)-3 = 5-3 | Subtraction property of equality. |
3 | (x+3)+(-3) = 5-3 | Definition of subtraction. |
4 | x+(3+(-3)) = 5-3 | Associative property of addition. |
5 | x+0 = 2 | Simplify both sides of the equation. |
6 | x = 2 | Property of addition by zero. |
7 | (2)+3 = 5 5 = 5 | Check work by substituting the solution back into the equation. |
Table 2: Solving x+3 = 5. |
Now start with the equation x-2 = 1. Since addition undoes subtraction, use the addition property of equality.
Step | Equation | Description |
---|---|---|
1 | x-2 = 1 | Original equation |
2 | (x-2)+2 = 1+2 | Addition property of equality. |
3 | (x+(-2))+2 = 1+2 | Definition of subtraction. |
4 | x+((-2)+2) = 1+2 | Associative property of addition. |
5 | x+0 = 3 | Simplify both sides of the equation. |
6 | x = 3 | Property of addition by zero. |
7 | (3)-2 = 1 1 = 1 | Check work by substituting the solution back into the equation. |
Table 3: Solving x-2 = 1. |
Start with the equation x÷3 = 6. Again, one wants to get the x by itself on one side of the equation. To undo multiplication, use division:
Step | Equation | Description |
---|---|---|
1 | x÷3 = 6 | Original equation |
2 | (x÷3)·3 = 6·3 | Multiplication property of equality. |
3 | x·(3÷3) = 6·3 | Associative property of multiplication. |
4 | x·1 = 18 | Simplify both sides of the equation. |
5 | x = 18 | Property of multiplication by 1. |
6 | 18÷3 = 6 6 = 6 | Check work by substituting the solution back into the equation. |
Table 4: Solving x÷3 = 6. |
When using division to solve an equation, one must be sure to not divide by zero. Since division by zero is undefined, division by zero will give undesirable and incorrect results. Start with the equation 3x = 6.
Step | Equation | Description |
---|---|---|
1 | 3x = 6 | Original equation |
2 | (3x)÷3 = 6÷3 | Division property of equality. |
3 | (x·3)÷3 = 6÷3 | Commutative property of multiplication. |
4 | x·(3÷3) = 6÷3 | Associative property of multiplication. |
5 | x·1 = 2 | Simplify both sides of the equation. |
6 | x = 2 | Property of multiplication by 1. |
7 | 3·2 = 6 6 = 6 | Check work by substituting the solution back into the equation. |
Table 5: Solving 3x = 6. |
The distributive property of multiplication over addition and subtraction is used often to solve an equation. The example in table 6 uses the distributive property to remove parenthesis.
Step | Equation | Description |
---|---|---|
1 | 3(x-4) = 3 | Original equation |
2 | 3·x-3·4 = 3 | Distributive property of multiplication over addition and subtraction. |
3 | 3x-12 = 3 | Simplify. |
4 | (3x-12)+12 = 3+12 | Addition property of equality. |
5 | (3x+^{-}12)+12 = 3+12 | Definition of subtraction. |
6 | 3x+(^{-}12+12) = 3+12 | Associative property of addition. |
7 | 3x+0 = 15 | Simplify. |
8 | 3x = 15 | Property of addition by zero. |
9 | x·3 = 15 | Commutative property of multiplication |
10 | x·3÷3 = 15÷3 | Division property of equality. |
11 | x·1 = 5 | Simplify both sides of the equation. |
12 | x = 5 | Property of multiplication by 1. |
13 | 3(5-4) = 3 3·1 = 3 3 = 3 | Check work by substituting the solution back into the original equation. |
Table 6: Solving 3(x-4) = 3. |
The example in table 7 uses the distributive property to combine two terms containing the same variable.
Step | Equation | Description |
---|---|---|
1 | 3x = 2x + 3 | Original equation |
2 | 3x - 2x = 2x - 2x + 3 | Addition property of equality. |
3 | 3x - 2x = 0 + 3 | Simplify. |
4 | 3x - 2x = 3 | Property of addition by zero. |
5 | x(3 - 2) = 3 | Distributive property of multiplication over addition and subtraction. |
6 | x·1 = 3 | Simplify. |
7 | x = 3 | Property of multiplying by 1. |
8 | 3·3 = 2·3 + 3 9 = 6 + 3 9 = 9 | Check work by substituting solution back into the equation. |
Table 7: Solving 3x = 2x + 3. |
This section describes how to use a TI-83 or TI-84 graphing calculator to find the middle root of x^{3}-0.5x^{2}-2x+1. Most graphing calculators have a way to solve equations graphically. Check the user manual for your calculator.
Step | Screen | Description |
---|---|---|
1 | Click the <CLEAR> button until you have a blank screen. | |
2 | Click the <Y=> button on the top row to view the graphing equation screen. If there are any equations showing, use the <CLEAR> key and the up and down arrows to erase all equations. Then click the up arrow key until it is in the top position. | |
3 | Enter the equation x^{3}-0.5x^{2}-2x+1 using the following keystrokes: <X,T,θ,n>, <^>, <3>, <->, <0>, <.>, <5>, <X,T,θ,n>, <x^{2}>, <->, <2>, <x>, <+>, <1>. | |
4 | Click on the <WINDOW> button to load the graphing window parameter screen. Use the number keys and the up and down arrow buttons to enter the window parameters as show in the screen image. When entering negative numbers, make sure to use the <(-)> key on the bottom row of the calculator. The key labeled <-> means subtract, not negate. | |
5 | Click the <GRAPH> button on the top row of the calculator. The graph of x^{3}-0.5x^{2}-2x+1 will appear in the window you specified. | |
6 | Click the <ZOOM> button to see the zoom menu. | |
7 | Click the down arrow button once to select menu option 2-Zoom In. | |
8 | Click the <ENTER> key on the bottom right corner of the calculator to return to the graph with the zoom option activated. | |
9 | Click the right arrow button until the cross hairs are near the middle intercept. The numbers at the bottom of the screen change to show you the coordinates of the cross hair. | |
10 | Click the <ENTER> button to zoom in on the zoom coordinates. | |
11 | Click on the left arrow button until the cross hairs are over the intercept. The zoom coordinates should be x=.5 and y=0. The correct intercept is x=0.5. You can click on the enter key again to make sure you are as close to the intercept as possible. | |
Table 8: Using the TI-83/84 calculator to find a root of x^{3}-0.5x^{2}-2x+1. |
If the discriminant b^{2} - 4ac is greater than zero, the quadratic equation has two real solutions. A real solution is a solution that is a real number. If the discriminant b^{2} - 4ac is 0, the quadratic equation has one real solution. If the discriminant b^{2} - 4ac is less than zero, the quadratic equation has two complex solutions. A complex solution is a solution that is a complex number.
Step | Equation | Description |
---|---|---|
Equation to solve | ||
1 | Substitute a = 2, b = -4 and c = -2 into the quadratic formula. | |
2 | Simplify exponents and multiplication inside the parenthesis. | |
3 | Simplify the subtraction inside the parenthesis. | |
4 | Since 32 = 16·2 and √16·2 = 4√2, rewrite the radical as 4√2. | |
5 | Use the distributive property of multiplication over addition and subtraction to split the fraction into two fractions. | |
6 | Simplify each fraction. | |
7 | Change the ± into two equations, one using + and the other using -. This quadratic equation has 2 solutions. | |
Table 9: Solving 2x^{2} - 4x - 2 = 0 using the quadratic formula. |
When solving a multiple variable equation, one solves for a variable. For example, given the equation x + y = 2, one can solve for the variable x or for the variable y. In this example we will solve for y.
x + y = 2 | Equation to solve in standard form |
x + y - x = 2 - x | Subtract x from both sides. |
y = 2 - x | Simplify the left side of the equation. |
y = -x + 2 | Put equation in slope/intercept form. |
Table 10: Solving for y |
# | A | B | C | D |
E | F | G | H | I |
J | K | L | M | N |
O | P | Q | R | S |
T | U | V | W | X |
Y | Z |
All Math Words Encyclopedia is a service of
Life is a Story Problem LLC.
Copyright © 2018 Life is a Story Problem LLC. All rights reserved.
This work is licensed under a Creative Commons Attribution-ShareAlike 4.0 International License