Perpendicular Bisector

Pronunciation: /ˌpɜr pənˈdɪk yə lər ˈbaɪ sɛk tər/ Explain
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Manipulative 1: Perpendicular bisector. Created with GeoGebra.

A perpendicular bisector is a line that bisects a line segment and is perpendicular to the line segment. In manipulative 1, line segment AB is the line segment being bisected. The red line is the perpendicular bisector. Point C is the midpoint of line segment AB. Click on the blue points in manipulative 1 and drag them to change the figure. To reset manipulative 1 back to its original configuration, click on the reset button (GGB Reset button) in the manipulative.

Properties of a Perpendicular Bisector

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Manipulative 2: Perpendicular bisector property. Created with GeoGebra.

Each point on a perpendicular bisector are the same distance from the endpoints. Since all points on a circle are the same distance from the center of the circle, two circles of the same size can be used to find a perpendicular bisector.

In manipulative 2, point D is the same distance from the center of each of the circles, meaning AD ≡ BD. As the radius AD changes, the points D and E are always on the perpendicular bisector. Click on point D and drag it to trace the perpendicular bisector.

The perpendicular bisectors of the sides of a triangle meet at the circumcenter of the triangle.

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Manipulative 3: Perpendicular bisectors of a triangle. Created with GeoGebra.

The perpendicular bisectors of the sides of a triangle intersect at a point called the circumcenter of the triangle.

Constructing a Perpendicular Bisector

Table 1 shows the steps to create a perpendicular bisector using a straight edge and a compass. Click on the blue points in each of the manipulatives and drag them to change the figure.
StepManipulativeDescriptionJustification
blank space Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now) Line segment AB is the line segment to bisect. These are the criteria.
1 Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now) Draw a circle with center A and radius AB. Euclid Elements Book 1 Postulate 3: A circle can be draw with any center and any radius.
2 Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now) Draw a circle with center B and radius BA. Euclid Elements Book 1 Postulate 3: A circle can be draw with any center and any radius.
3 Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now) Mark the intersections of the circles as points C and D. An intersection is a point of concurrency.
4 Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now) Draw a line through points C and D. This line is the perpendicular bisector. Euclid. Elements Book 1 Postulate 1. A line can be drawn from any point to any point.
5 Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now) The intersection of line segment AB and line segment CD is the midpoint of line segment AB An intersection is a point of concurrency.
Table 1: Constructing a perpendicular bisector.

Equation of a Perpendicular Bisector

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Manipulative 4: Equation of a perpendicular bisector. Created with GeoGebra.

The equation of a perpendicular bisector can be calculated for a given line segment with end points (x1,y1) and (x2,y2). This demonstration will show how to calculate the equation of a perpendicular bisector in point slope form. Click on the points in manipulative 4 and drag them to change the figure.

StepEquationDescription
1 p=((x2+x1)/2,(y2+y1)/2) gives p=0.5 First calculate the location of midpoint.
2 m=((y2-y1)/(x2-x1)) gives m=-1.25 Calculate the slope of the line segment AB.
3 m1=-1/m gives m1=0.8 Calculate the slope of the perpendicular line using the slope of line segment AB.
4 y-y0=m1(x-x0) gives y-0.5=0.8(x-0) Put the slope of the perpendicular line and the coordinates of the midpoint into and equation in point slope form.
Table 2: Calculating the equation of a perpendicular bisector

More Information

  • Dendane, A. Perpendicular Bisector. Analyze Math. 3/12/2009. http://www.analyzemath.com/Geometry/PerpendicularBisector/PerpendicularBisector.html.

Cite this article as:

McAdams, David E. Perpendicular Bisector. 8/7/2018. All Math Words Encyclopedia. Life is a Story Problem LLC. http://www.allmathwords.org/en/p/perpendicularbisector.html.

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Revision History

8/7/2018: Changed vocabulary links to WORDLINK format. (McAdams, David E.)
11/15/2008: Initial version. (McAdams, David E.)

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